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x^2+2.2x-880=0
a = 1; b = 2.2; c = -880;
Δ = b2-4ac
Δ = 2.22-4·1·(-880)
Δ = 3524.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.2)-\sqrt{3524.84}}{2*1}=\frac{-2.2-\sqrt{3524.84}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.2)+\sqrt{3524.84}}{2*1}=\frac{-2.2+\sqrt{3524.84}}{2} $
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